Class 12 Physics Top 10 Must-Know 5-Mark Derivations with Proofs (CBSE & BSEB 2026/2027)
PrepOne Academic Team
September 18, 2026
15 min read
Summary: This master revision guide covers the Top 10 most repeated 5-mark derivations in Class 12 Physics for CBSE and State Boards (BSEB). Each derivation includes the statement, diagram blueprint, step-by-step mathematical proof, and examiner step-marking distribution.
In both CBSE (Section E, 3 questions × 5 marks = 15 marks) and Bihar Board (Section B, 3 questions × 5 marks = 15 marks), long-answer questions are almost exclusively drawn from a pool of foundational derivations. Mastering these 10 derivations secures full marks on the theoretical component of your physics board paper.
Top 10 Physics Derivations Directory
1. Electric Field Due to an Infinitely Long Straight Wire (Gauss's Law)
Unit I: Electrostatics
Consider an infinitely long thin wire having uniform linear charge density λ. By cylindrical symmetry, choose a coaxial Gaussian cylinder of radius r and length l.
∮E⋅dA=∫curvedEdAcos0∘+∫endsEdAcos90∘=E(2πrl)
qenclosed=λl
By Gauss’s Law: E(2πrl)=ε0λl⟹E=2πε0rλ
Examiner Tip: State explicitly that the flux through the circular flat caps is zero because E⊥dA (cos90∘=0).
2. Electric Field Due to a Uniformly Charged Thin Spherical Shell
Unit I: Electrostatics
Let a thin spherical shell of radius R carry total charge Q=4πR2σ. Construct a concentric spherical Gaussian surface of radius r.
Case 1: Outside Shell (r≥R):∮EdA=E(4πr2)=ε0Q⟹E=4πε01r2Q=ε0r2σR2
Case 2: Inside Shell (r<R):qenclosed=0⟹E(4πr2)=0⟹E=0
3. Parallel Plate Capacitor with Dielectric Slab of Thickness t<d
Unit I: Electrostatics
Plates of area A separated by distance d. In vacuum thickness (d−t), electric field is E0=ε0σ. Inside dielectric of thickness t, field is E=KE0.
4. Drift Velocity and Microscopic Deduction of Ohm's Law
Unit II: Current Electricity
Free electrons under electric field E experience acceleration a=−eE/m. With mean relaxation time τ, drift velocity is vd=meEτ.
I=neAvd=neA(meEτ)=(mne2τ)AE=σAE
Since E=lV,I=(mlne2τA)V⟹V=(ne2τmAl)I=RI
where Resistivity ρ=ne2τm
5. Magnetic Field on the Axis of a Circular Current Loop (Biot-Savart Law)
Unit III: Magnetism
Radius R, current I, point P at axial distance x. Resolving dB into components; perpendicular components cancel by symmetry:
B=∮dBx=∮dBcosϕ=4π(R2+x2)μ0IR2+x2R∮dl
B=4π(R2+x2)3/2μ0IR(2πR)=2(R2+x2)3/2μ0IR2
6. Magnetic Field Inside a Long Solenoid (Ampère's Law)
Unit III: Magnetism
Consider a rectangular Ampèrian loop abcd of length L. The magnetic field outside is negligibly weak (B≈0), and along perpendicular segments bc and da, B⊥dl.
∮B⋅dl=∫abBdl=BL
Ienclosed=nLI(n=turns per unit length)
BL=μ0(nLI)⟹B=μ0nI
7. Mutual Inductance of Two Long Coaxial Solenoids
Unit IV: Electromagnetic Induction
Two coaxial solenoids S1 (radius r1, turns n1) and S2 (radius r2>r1, turns n2). When current I2 flows in S2, field inside is B2=μ0n2I2.
By Thin Lens Formula (v1−u1=f1):f1=(μ−1)(R11−R21)
9. Proof of Laws of Refraction Using Huygens' Wavefront Theory
Unit VI: Wave Optics
A plane wavefront AB is incident at angle i on interface separating medium 1 (speed v1) from medium 2 (speed v2). Time taken for secondary wavelet to travel from B to C is τ=BC/v1.
sini=ACBC=ACv1τ,sinr=ACAE=ACv2τ
sinrsini=v2v1=c/v1c/v2=μ1μ2=μ(Snell’s Law Verified)
10. Magnifying Power of Astronomical Telescope (Normal & Near Point Adjustment)
Unit VI: Optics
An astronomical telescope consists of an objective (fo, large aperture) and an eyepiece (fe, small aperture).
Normal Adjustment (Image at ∞):m=−fefo,L=fo+fe
Near Point Adjustment (Image at D=25 cm):m=−fefo(1+Dfe),L=fo+ue
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